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Using a property of Logarithms Demonstrate that

In x/In y≠ Inx/y = In x - In y
by using a spreadsheet to complete the table.
x y Inx/Iny Inx/y In x - In y
1 2
3 4
10 5
4 0.5

User Goulou
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1 Answer

4 votes

Answer:

Dividing logarithms is not the same as dividing the arguments of a logarithm.

Explanation:

1) If we divide two logarithms then we'll find a value. This is not the same as dividing two arguments of the same base logarithms.

For example:


\\ (ln3)/(ln2)=1.58\\eq ln \left ( (3)/(2) \right )= ln3-ln2=0.405

Then


\\ (lnx)/(lny)\\eq ln \left ( (x)/(y) \right )= lnx-lny

2) Completing the table below to show it clearly:

Using a property of Logarithms Demonstrate that In x/In y≠ Inx/y = In x - In y by-example-1
User You Knows Who
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