Question

On average, a tree produces 118 kilograms of oxygen a year. How many molecules of carbon dioxide must a tree take in each year in order to accomplish this? (don't forget to convert kilograms to grams)

a. 1.23 x 1032
b. 2.22 x 1027
c. 3.24 x 1029
d. 3688.9

Answer 1

1. no. of moles of Oxygen = 3687.5 mol

2. amount of CO₂ taken = 3687.5 moles

3. Option B is correct = 2.22 x 10²⁷

Step-by-step explanation:

Data Given:

Amount of O₂ = 118 Kg

moles of O₂ = ?

no. of molecules of CO₂ = ?

Solution:

First we have to convert Kg to g

Convert unit from Kg to g

1 Kg = 1000 g

118 Kg = 118 x 1000 = 118000 g

Now we will find number of moles of O₂

Mole formula will be used

no. of moles = mass in grams/ molar mass

molar mass of O₂ = 2(16) = 32 g/mol

Put values in mole formula

no. of moles = 118000 g/ 32 g/mol

no. of moles = 3687.5 mol

So we have 3687.5 moles of Oxygen

__________________

Part 2:

Now we have to find moles of CO₂ taken by plant to to produce 3687.5 moles of Oxygen

First we will look for the reaction by

6 CO₂ + 6 H₂O ---------> 6 C₆H₆O₆ + 6 O₂

So,

6 CO₂ + 6 H₂O ---------> 6 C₆H₆O₆ + 6 O₂

6 mole 6 mole

So from the above reaction we come to know that 6 moles of CO₂ will be taken to produce 6 moles of O₂

As we Know,

6 moles of CO₂ ≅ 6 moles of O₂

So,

3687.5 moles of CO₂ ≅ 3687.5 moles of O₂

So amount of CO₂ taken = 3687.5 moles

_________________________

Part 3

Now we will find number of molecules of CO₂

Mole formula will be used

no. of moles = no. of molecules / Avogadro's number

Rearrange the above formula

no. of molecules = no. of moles x Avogadro's number . . . . . (1)

Avogadro's number = 6.022 x 10²³

Put values in mole formula (1)

no. of molecules = 3687.5 moles x 6.022 x 10²³

no. of molecules = 2.22 x 10²⁷

So ,

Option B is correct = 2.22 x 10²⁷