Question

2 3 ​ y−3+ 3 5 ​ zstart fraction, 3, divided by, 2, end fraction, y, minus, 3, plus, start fraction, 5, divided by, 3, end fraction, z when y=6y=6y, equals, 6 and z=3z=3z, equals, 3.

Answer 1

11

Explanation:

1) This expression can be solved simply by plugging in the given conditions y=6 and z=3.

`(3)/(2)y-3+(5)/(3)z\:When\: y=6\:z=3 \Rightarrow \\(3)/(2)*(6)-3+(5)/(3)*(3) \Rightarrow 9-3+5=11`