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2 votes
If the area of a rectangle is 42 m² and its length is 7 m then its width is

m and its perimeter is
m.

User Tayla
by
6.5k points

1 Answer

6 votes

Answer:

width = 6 m
preimiter = 26 m

Explanation:

I find it always helps to write down what we are given
A (area) = 42
l (length) = 7
w (width) = ?

We also know that the formula for the area of a rectangle is A=lw or Area equals length times width. From here we can substitue the information we are given to solve for the unknown.

A = lw
42 = 7w
divide both sides by 7 to isolate w
42/7 = 7/7 * w
6 = 1* w
w = 6m

Now that we know the width, we can use that information to find the perimiter. The perimiter of a rectangle is the sum of all of the sides, which is the equivalent of two lengths plus two widths, and can be solved with the formula:
P = 2l+2w -or- P = l+l+w+w
Either way, we get the same answer

P = 2(6)+2(7)
P = 12+14
P = 26 m

User Walia
by
6.5k points
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