Answer:
Explanation:
Functions
The problem describes a function that expresses the concentration of an antibiotic in mg/dl vs time in hours as:
![\displaystyle c(t)=(50\ t)/(t^2+25)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/p4cc03zi20aaf6nvatvy015h2htvn881z6.png)
We need to find the first value of t such that
![\displaystyle c(t)\geq 4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9n4meqz2uhrytznpx73t62kzsgwrp0xl2a.png)
It means that
![\displaystyle (50\ t)/(t^2+25)\geq 4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/e7egxku1bu6ukojctcrz4dxxxej7xs14pw.png)
Operating with the inequality
![\displaystyle 50\ t\geq 4\ t^2+100](https://img.qammunity.org/2021/formulas/mathematics/middle-school/daagk4lu0mbuqdswtemovfq1nal4eqjp5d.png)
Rearranging and dividing by 2, we have a polynomial inequality:
![\displaystyle 2t^2-25t+50\leq 0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9pian9wkiaa5ghn14ekfzpz34u3oo73izu.png)
Factoring
![\displaystyle 2(t-10)\left (t-(5)/(2)\right )\leq 0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ig8hp283s9bt85cj7oyth7vaq8zm3zgqmr.png)
There are two possible values for t, both valids because they are positive
![\displaystyle t=(5)/(2)=2.5, \ t=10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l0det5j550tl2h6bkv3csmvgj2kplu7ruf.png)
We need to find the first value, i.e.
![t=2.5 \ hours](https://img.qammunity.org/2021/formulas/mathematics/middle-school/o75gl5pzfvt58seks053mdf6g77zral2cw.png)
Now for the graphic method, we plot the graph for the function and a horizontal line at c=4 to find the values of t.
The graph is shown in the image provided below. We can see both values where the funcion and C=4 intersect. Both values coincide with the previously analitically found values