Answer:
There will participate 14.4 grams of bromine
Step-by-step explanation:
Step 1: Data given
Liquid bromine is Br2
Numbers of moles of bromine liquid = 0.0900 moles
Molar mass of Br = 79.9 g/mol
Molar mass of Br2 = 2* 79.9 = 159.8 g/mol
Step 2: Calculate the mass of bromine that will participate
Mass = moles * molar mass
Mass bromine = 0.0900 moles * 159.8 g/mol
Mass bromine = 14.4 grams
There will participate 14.4 grams of bromine