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spring is compressed 4.2 cm. If a box is placed at the end of the compressed spring, and let go, how far up the ramp will the spring cause the box to travel? Ignore any frictional effects.

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Answer:

0.81 m

Step-by-step explanation:

K= 36 N/m

θ= 30°

mass m = 8 kg

let the distance moved by the box be d

We can solve this using

Apply conservation of energy


(1)/(2)kx^2= mg sin\theta* d

d= 1/2×k×x^2/ mg sinθ


d= (1)/(2)*36(0.042)^2/8*9.81sin30

d = 0.81 m

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