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It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the elevator during the process? Explain your answer.

User Sanja
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1 Answer

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Answer:

4.80 kW

Step-by-step explanation:

Power = work / time

P = 100,832 J / 21.0 s

P ≈ 4800 W

User Trinh
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