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Create the quadratic function that contains the points (0, -2).(1,0), and (3, 10). Show all of your work

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Answer:

y = 4/3 (x + 3/4)(x - 1)

Explanation:

Notice in the given pints that (1,0) is an x-intercept. Use the quadratic function form in x-intercept form and substitute the one x-intercept.

y = a(x-s)(x-s)

y = a(x-1)(x-s)

Substitute the two other points as x and y.

10 = a(3-1)(3-s) Substituted point (3,10)

-2 = a(0-1)(0-s) Substituted point (0, -2)

Simplify or rearrange the equations and see what can be substituted.

10 = a(3-1)(3-s)

10 = 2a(3-s)

10 = 6a - as

-2 = a(0-1)(0-s)

-2 = (-a)(-s)

-2 = as Notice "as" is also in the other formula.

Substitute -2 for as

10 = 6a - as

10 = 6a - (-2)

10 = 6a + 2

8 = 6a

a = 8/6

a = 4/3

Include a=4/3 in the quadratic function in x-intercept form.

y = a(x-1)(x-s)

y = (4/3)(x-1)(x-s) Substitute random point (3,10) and find "s"

10 = (4/3)(3-1)(3-s)

10 = (4/3)(2)(3-s)

10 = (4/3)(6 - 2s)

10 = 8 - (8/3)s

2 = -(8/3)s

s = 2 รท -8/3

s = -0.75 = -3/4

You can write the equation in x-intercept form.

y = 4/3 (x + 3/4)(x - 1)

You can expand to write in standard form.

User Kirstan
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