Answer:
Explanation:
Given is a function f(x)
![f(x) = x^2 e^(-x)](https://img.qammunity.org/2021/formulas/mathematics/college/6mrhkdbll5579gcynpk2fuqg5n0amakhwu.png)
We have to analyse and sketch the grapy
X intercept : Put y =0, we get x =0 or infinity
Y intercept: Put x =0 , we get y =0
The function being product of a square divided by power of e can never be negative. Hence range is (0,infty)
Since when y=0 x has a solution as infinity, x axis is asymptote
![f'(x) = (2x -x^2)e^(-x)](https://img.qammunity.org/2021/formulas/mathematics/college/fx15c0oh1c210xt2xd2t3l8r2qpw9578ap.png)
f' becomes 0 when x = 0 or 2
f"(x) >0 for x=2 and <0 for x=0
Hence maxima at x=2 and minima at x=0
Graph is attached below