Question

It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the elevator during the process?

Answer 1

P=4801.5

Step-by-step explanation:

Given :

work done = W = 100,832 J

time = 21.0 sec

Find:

P = ?

Formula:

P = W/t

Solution:

P = W/t

P = 100,832/21.0

= 4801.52 J/s or Watts