Question

while doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm^3. the accepted value for the density of aluminum is 2.70 g/cm^3. The accepted value for density of aluminum is 2.70 g/cm^3. What was the student's percent error?

Answer 1

The student's percent error in the density measurement of aluminum is calculated as |(2.85 - 2.70) / 2.70| × 100%, which equals 5.56%.

Step-by-step explanation:

The student's percent error in determining the density of a piece of pure aluminum can be calculated using the formula:
Error = (experimental value - accepted value) / accepted value × 100%.

The experimental value is 2.85 g/cm³, and the accepted value is 2.70 g/cm³. Plugging these values into the formula gives:

Error = |(2.85 - 2.70) / 2.70| × 100%
Error = |0.15 / 2.70| × 100%
Error = 0.0556 × 100%
Error = 5.56%

This means the student's percent error in measuring the density of aluminum is 5.56%.

Answer 2

Percent error = 5.6%

Step-by-step explanation:

Given data:

Measured value of density by students = 2.85 g/cm³

Accepted density of aluminium = 2.70 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [ Measured value - accepted value / accepted value ]× 100

Now we will put the values in formula:

Percent error = [ 2.85 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ]× 100

Percent error = [0.15/2.70 g/cm³ ] × 100

Percent error = 0.056× 100

Percent error = 5.6%