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Find a+b,2a+3b,IaI, and Ia-bI. a[2, -4, 4], b=[0, 2, -1]

1 Answer

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Answer:

a+b = [2, -2, 2]

a+3b = [2,2,1]

|a| = 6


|a-b|=√(65)

Explanation:


a+b = [2+0,-4+2,4-1]=[2,-2,2]


a+3b = [2+0,-4+6,4-3]=[2,2,1]


|a|=]sqrt{4+16+16}=√(36)=6


|a-b|=|√((2-0)^2+(-4-2)^2+(4+1)^2)|=√(4+36+25)=√(65)

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