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How many roots of the polynomial 30x^4 + 7x^3-125x^2-54x+72 have absolute value greater than 1?

User Braydon
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1 Answer

4 votes

Answer:

There are 3 roots of the given polynomial that have absolute value greater than 1.

Explanation:

We are given the polynomial:


p(x) = 30x^4 + 7x^3-125x^2-54x+72

We can factorize the given polynomial as:


p(x) = 30x^4 + 7x^3-125x^2-54x+72\\=(x-2)(2x+3)(5x-3)(3x+4)=0


\text{Solving for}\\(x-2) = 0\\x = 2\\|x| = 2 > 1


\text{Solving for}\\(2x+3) = 0\\x = (-3)/(2)\\\bigg|(-3)/(2)\bigg| = (3)/(2) > 1


\text{Solving for}\\(5x-3) = 0\\x = (3)/(5)\\\bigg|(3)/(5)\bigg| = (3)/(5) < 1


\text{Solving for}\\(3x+4) = 0\\x = (-4)/(3)\\\bigg|(-4)/(3)\bigg| = (4)/(3) > 1

Thus, there are 3 roots of the given polynomial that have absolute value greater than 1.

User SstrykerR
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