Answer:
See the graph and explanation below.
Explanation:
For this case we have the following function:

We can calculate some points in order to see the tendency of the graph, we can select a set of points for example
and we can calculate the values for f(x) like this
x=-2

x=-1.5

x=-1

x=0

This point correspond to the y intercept.
x=1

x=2

We don't have x intercepts for this case since the functionnever crosses the x axis.
And then we can see the plot on the figure attached.