Question

In Exercise,discuss the continuity of the function.
f(x) = x^2-6x+5/x^2-3

Answer 1

The function f(x) = x^2-6x+5/x^2-3 is discontinuous at
`x= √(3)` and
`x= -√(3)`

Explanation:

The function is discontinuous at the roots of denominator
`x^(2) -3=0` which are
`x= √(3)` and
`x= -√(3)`.

The function f(x) = x^2-6x+5/x^2-3 has also two vertical asymptotes at these points.

The Graph of the function is attached. One horizontal asymptote can also be identified at y=1