Question

Find the average value of the function on the given interval.
f(x)=x^2-4; [0,5]

Answer 1

Average=29/6=4.83

Explanation:

F(0)=0^2-4=-4

F(1)=1^2-4=-3

F(2)=2^2-4=0

F(3)=3^2-4=5

F(4)=4^2-4=10

F(5)=5^2-4=21

The average is =total/6

Average=29/6=4.83