Question

In Exercise,discuss the continuity of the function.
f(x) = x+1/x^2-4

Answer 1

the function f(x) = (x+1)/(x^2-4) is discontinuous at x=2 and at x=-2

Explanation:

The function is discontinuous at the roots of the denominator x^2-4, which are at x=2 and x=-2.

The function f(x) =(x+1)/(x^2-4) has also two vertical asymptotes at these points.

The Graph of the function is attached. One horizontal asymptote can also be identified at y=0