Question

Apply the Henderson-Hasselbalch equation to calculate the CH3NH3'/ CH3NH2 ratio in water buffered at PH 7.

Answer 1

`([CH_3NH_3^+])/([CH_3NH_2])=4168.69`

Step-by-step explanation:

As we know that:-

For
`CH_3NH_2`:-

`pK_(b)=3.38`

pH = 7

Also, pH + pOH = 14

So, pOH = 14 - 7 = 7

Considering the Henderson- Hasselbalch equation for the calculation of the pOH of the basic buffer solution as:

`pOH=pK_b+log([CH_3NH_3^+])/([CH_3NH_2])`

So,

`7=3.38+log([CH_3NH_3^+])/([CH_3NH_2])`

`log([CH_3NH_3^+])/([CH_3NH_2]) = 7-3.38=3.62`

`([CH_3NH_3^+])/([CH_3NH_2])=4168.69`