Answer:
4.21 grams of silver chloride are produced
Step-by-step explanation:
Let's follow the reaction:
2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂
Ratio is 2:2 so 2 moles of nitrate produce, 2 mol of chloride.
Mol = Mass / Molar mass → 5g / 169.87 g/m = 0.0294 moles
So, 0.0294 moles of Silver chloride are produced
Molar mass AgCl = 143.32 g/m
Molar mass . mol = Mass → 143.32 g/m . 0.0294 mol = 4.21 grams