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Spent 100 earlier and it didn't work could someone help me really quick?

Spent 100 earlier and it didn't work could someone help me really quick?-example-1
Spent 100 earlier and it didn't work could someone help me really quick?-example-1
Spent 100 earlier and it didn't work could someone help me really quick?-example-2
User Waldo
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1 Answer

21 votes
21 votes

Answer:

(a) linear

(b) non-linear quadratic

(c) non-linear

Explanation:

In order to find first differences, we need to find the differences in the y-values. This only works if the differences in the x-values are constant, so we must first check the x-values. If the differences in the x-values are constant, and the differences in the y-values are constant, the relation is linear. If the differences in the x-values are constant, but the differences in the y-values are NOT constant, then relation is non-linear.

A non-linear relation is quadratic if the second difference of the y-values is constant.

(a) From inspection, we can see that the x-values increase by 10 each time. Therefore, the difference in the x-values is constant.

Comparing the y-values, we can see that they increase by 20 each time, and so their difference is also constant.

Difference in y-values:

41 - 21 = 20

61 - 41 = 20

81 - 61 = 20

Therefore, as the differences in x-values and y-values is constant, we can confirm that this relation is linear.

(b) From inspection, we can see that the x-values increase by 1 each time. Therefore, the difference in the x-values is constant.

Comparing the y-values, we can see that they DO NOT decrease by the same amount each time, and so their difference is NOT constant.

Difference in y-values:

-3 - (-2) = -1

-5 - (-3) = -2

-8 - (-5) = -3

Therefore, as the differences in x-values is constant yet the differences in y-values is not constant, we can confirm that this relation is non-linear.

Second difference in y-values:

-2 - (-1) = -1

-3 - (-2) = -1

Therefore, as the second difference in y-values is constant, the relation is quadratic.

(c) From inspection, we can see that the x-values increase by 1 each time. Therefore, the difference in the x-values is constant.

Comparing the y-values, we can see that they DO NOT increase by the same amount each time, and so their difference is NOT constant.

Difference in y-values:

-1 - (-2) = 1

6 - (-1) = 7

25 - 6 = 19

Therefore, as the differences in x-values is constant yet the differences in y-values is not constant, we can confirm that this relation is non-linear.

Second difference in y-values:

7 - 1 = 6

19 - 7 = 12

Therefore, as the second difference in y-values is NOT constant, the relation is NOT quadratic.

User Roonaan
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