Question

You react 105g of lithium nitride and excess water, and you get 48g of lithium hydroxide. What is the percent yield?

Answer 1

Percent yield = 22.26%

Step-by-step explanation:

Given data:

Mass of lithium nitride = 105 g

Mass of lithium hydroxide produces = 48 g

Percent yield = ?

Solution:

Chemical equation:

Li₃N + 3H₂O → 3LiOH + NH₃

Number of moles of lithium nitride :

Number of moles = mass/ molar mass

Number of moles = 105 g/ 34.83 g/mol

Number of moles = 3 mol

Now we will compare the moles of lithium nitride with lithium hydroxide.

Li₃N : LiOH

1 : 3

3 : 3×3 = 9 mol

Mass of lithium hydroxide:

Mass = number of moles × molar mass

Mass = 9 mol × 23.95 g/mol

Mass = 215.6 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 48 g/ 215.6 g × 100

Percent yield = 22.26%