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Differentiating Functions of Other Bases In Exercise, find the derivative of the function.

y = log10 3/x

User IluSioN
by
4.9k points

1 Answer

7 votes

Answer:


y' = -(1)/(2.3x)

Explanation:

The derivative of
a*x^(n) is
a*n*x^(n-1). The derivative of
3x^(-1) is
-3x^(-2), for example.

Derivative of the log function:


y = log_a(f(x))

Has the following derivative


y' = (f'(x))/(ln(a)*f(x))

In this problem, we have that:


y = \log_(10){(3)/(x)}

So


a = 10, f(x) = (3)/(x) = 3x^(-1), f'(x) = -3x^(-2)

The derivative of the function is:


y' = (f'(x))/(ln(a)*f(x))


y' = (-3x^(-2))/(2.3*3x^(-1))


y' = -(1)/(2.3x)

User Hana Alaydrus
by
5.7k points
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