16.3k views
18 votes
Spent 100 earlier and it didn't work could someone help me really quick?

Spent 100 earlier and it didn't work could someone help me really quick?-example-1
Spent 100 earlier and it didn't work could someone help me really quick?-example-1
Spent 100 earlier and it didn't work could someone help me really quick?-example-2
User Masfenix
by
7.8k points

1 Answer

8 votes

Answer:

(a) linear

(b) non-linear quadratic

(c) non-linear

Explanation:

In order to find first differences, we need to find the differences in the y-values. This only works if the differences in the x-values are constant, so we must first check the x-values. If the differences in the x-values are constant, and the differences in the y-values are constant, the relation is linear. If the differences in the x-values are constant, but the differences in the y-values are NOT constant, then relation is non-linear.

A non-linear relation is quadratic if the second difference of the y-values is constant.

(a) From inspection, we can see that the x-values increase by 10 each time. Therefore, the difference in the x-values is constant.

Comparing the y-values, we can see that they increase by 20 each time, and so their difference is also constant.

Difference in y-values:

41 - 21 = 20

61 - 41 = 20

81 - 61 = 20

Therefore, as the differences in x-values and y-values is constant, we can confirm that this relation is linear.

(b) From inspection, we can see that the x-values increase by 1 each time. Therefore, the difference in the x-values is constant.

Comparing the y-values, we can see that they DO NOT decrease by the same amount each time, and so their difference is NOT constant.

Difference in y-values:

-3 - (-2) = -1

-5 - (-3) = -2

-8 - (-5) = -3

Therefore, as the differences in x-values is constant yet the differences in y-values is not constant, we can confirm that this relation is non-linear.

Second difference in y-values:

-2 - (-1) = -1

-3 - (-2) = -1

Therefore, as the second difference in y-values is constant, the relation is quadratic.

(c) From inspection, we can see that the x-values increase by 1 each time. Therefore, the difference in the x-values is constant.

Comparing the y-values, we can see that they DO NOT increase by the same amount each time, and so their difference is NOT constant.

Difference in y-values:

-1 - (-2) = 1

6 - (-1) = 7

25 - 6 = 19

Therefore, as the differences in x-values is constant yet the differences in y-values is not constant, we can confirm that this relation is non-linear.

Second difference in y-values:

7 - 1 = 6

19 - 7 = 12

Therefore, as the second difference in y-values is NOT constant, the relation is NOT quadratic.

User Rbanffy
by
7.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.