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Differentiating a Logarithmic Function In Exercise, find the derivative of the function.

y =In (x^2 - 2)2/3

User RazvanDH
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1 Answer

7 votes

Answer:


y' = (4x)/(3(x^(2) - 2))

Explanation:

The derivative of
(f(x))^(n) is
f'(x)*n*(f(x))^(n-1). The derivative of
(20x^(2) + 3)^(10) is
400x*(20x^(2) + 3)^(9), for example.

We also have that the derivative of


y = ln(f(x))

Is


y' = (f'(x))/(f(x))

In this problem, we have that:


y = \ln{(x^(2)-2)^{(2)/(3)}}

So


f(x) = (x^(2) - 2)^{(2)/(3)}


f'(x) = (2*2x)/(3)*(x^(2) - 2)^{-(1)/(3)}

The derivative of the function is:


y' = (f'(x))/(f(x))


y' = \frac{(2*2x)/(3)*(x^(2) - 2)^{-(1)/(3)}}{(x^(2)-2)^{(2)/(3)}}


y' = (4x)/(3(x^(2) - 2))

User Waqas Ali
by
7.3k points