Answer:
Dy/Dx=x ( 2 ln ( x ) − 1 )/ ln ^2 ( x)
Explanation:
We have this function and let's derive it in terms of x.
y =x^2/In x
Dy/Dx=(x^2/In x)'=2/lnx *(x^2)'-(x^2/In x)'=> 2 x *ln ( x ) − x *ln ^2 ( x ) =x ( 2 ln ( x ) − 1 )/ ln ^2 ( x)
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