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At 9:00am cyclist A off on a trail at an average speed of 16km/h. At 10:00am cyclist B off from the same place, in the same direction at an average speed of 24km/h. At what time will cyclist Bcatch up
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At 9:00am cyclist A off on a trail at an average speed of 16km/h. At 10:00am cyclist B off from the same place, in the same direction at an average speed of 24km/h. At what time will cyclist Bcatch up with cyclistA

User Luigibertaco
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3 votes

Answer:

noon

Explanation:

Cyclist B gains on Cyclist A at the rate of 24 -16 = 8 km/hour. Cyclist A has a 1-hour, or 16 km, head start. Cyclist B will make up that difference in 2 hours, at 12:00 pm (noon).

User Anton Bogdanov
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