Question

A stone thrown from a height of 5.72 meters hits the ground at 13.3, Calculate the initial speed. Neglect air resistance

Answer 1

12.31618 m/s

Step-by-step explanation:

s = Displacement

t = Time taken

g = Acceleration due to gravity = 9.81 m/s² = a

`s=ut+(1)/(2)at^2\\\Rightarrow 5.72=0t+(1)/(2)* 9.81* t^2\\\Rightarrow t=\sqrt{(5.72* 2)/(9.81)}\\\Rightarrow t=1.07988\ s`

Velocity is given by

`v=(s)/(t)\\\Rightarrow v=(13.3)/(1.07988)\\\Rightarrow v=12.31618\ m/s`

The initial velocity is 12.31618 m/s