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Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as the sum, difference, or multiple of logarithms.

In x^2/x^2 + 1

User Beduin
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Answer:


\\ ln(x^2) - ln(x^2 + 1).

For values of x>0, it can be rewritten as
\\ 2ln(x) - ln(x^2 + 1).

Explanation:

For the expression:


\\ ln((x^2)/(x^2 + 1))

We can apply this logarithmical property:
\\ ln((x)/(y)) = ln(x) - ln(y).

Then,


\\ (x^2)/(x^2 + 1) = ln(x^2) - ln(x^2 + 1).

If we assume values of x > 0 (non negative values for x), then the expression could be rewritten as follows:


\\ (x^2)/(x^2 + 1) = ln(x^2) - ln(x^2 + 1) = 2 ln(x) - ln(x^2 + 1), since
\\ ln(x^(n)) = n*ln(x).

We have to remember that domain (all possible values x) for logarithmic function is for all x > 0, or mathematically expressed as:

Domain:
\\ x

User Dasper
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