Question

in a quiz progam, 3 questions on sport, 3 question on General Knowlegde, and 4 questions on science are print sepraretly pn 10 cards and place upside down. John is asked to select 2 cards at random. What is the probabitly of john selecting 2 question on science

Answer 1

Answer:2/15

Explanation:

Answer 2

Answer:
`(2)/(15)`

Explanation:

Given : Number of questions on sport = 3

Number of questions on General Knowledge = 3

Number of questions on science = 4

Each question printed on separate card , Total cards = 10

Number of ways to select any 2 card out of 10 =
`C(10,2)=(10!)/(2!(10-2)!)=(10*9*8!)/(2*8!)=45` →Total outcomes

Number of ways to select any 2 card out of 4 =
`C(4,2)=(4!)/(2!(4-2)!)=(4*3*2!)/(2*2!)=6` → Favorable outcomes

Now , the probability of John selecting 2 question on science =
`\frac{\text{Favorable outcomes}}{\text{Total outcomes}}`

`=(6)/(45)=(2)/(15)`

Hence, the required probability is
`(2)/(15)` .