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Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Label any relative extrema, points of inflection, and asymptotes.

f(x) = x3ex

User Armatorix
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1 Answer

3 votes

Answer:

Sketched & Analyzed.

Explanation:

We are given:
f(x)=x^3e^x

First derivative of f(x):


f'(x)=3x^2e^x+x^3e^x=x^2e^x(x+3)

There are a root at x = -3 and double roots at x = 0.

So it is decreasing on (-∞, -3) and increasing on (-3, ∞).

Second derivative of f(x):


f''(x)=e^xx^3+6e^xx^2+6e^xx=xe^x(x^2+6x+6)

Roots are
x = 0,\: x = -3-\sqrt3, \:x=-3+\sqrt3

So it is concave down on
(-\infty,-3-\sqrt3)
(-3-\sqrt3,0) and concave up on
(-3-\sqrt3,-3+\sqrt3)
(0,\infty)

The sketch is given in the attachment.

Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Label-example-1
User EstuansInterius
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4.9k points