Answer:
NO2
Step-by-step explanation:
To calculate the empirical formula, what we need do first is to divide the appropriate percentage compositions with the atomic masses. The atomic mass of nitrogen is 14g/mol. The atomic mass of oxygen is 16g/mol
We proceed like this:
N = 30.45/14 = 2.175
O = 69.55/16 = 4.347
We then divide both by the smallest of the numbers.
N = 2.175/2.175 = 1
O = 4.347/2.175 = 2
The empirical formula is thus NO2