Question

To get to school, Grayson usually walks 1.5 miles west and 0.8 miles north on the sidewalks. Because he is in a hurry, he has decided to take a shortcut across the field. How many miles does Grayson have to walk across the field?

Answer 1

Grayson has to walk 1.7 miles across the field.

Explanation:

We have drawn the diagram for your reference.

Given:

Grayson usually walks 1.5 miles west on the side walks

According to Diagram we can say;

CA = 1.5 miles

Also Given:

Grayson also walks 0.8 miles north on the sidewalks

So According to Diagram we can say;

BA =0.8 miles

Now we need to find number of miles Grayson have to walk across the field.

According to diagram we can say;

We have to find CA.

Assuming the diagram to be right angled triangle.

We can find CA using Pythagoras theorem.

`{CA}^2 = {CB}^2+{BA}^2`

Substituting the given values we get;

`{CA}^2 =1.5^2+0.8^2 = 2.25 +0.64 =2.89`

Taking square root on both side we get;

`\sqrt{{CA}^2} = √(2.89) \\\\CA = 1.7 \ mi`

Hence Grayson has to walk 1.7 miles across the field.