Answer:
250.
Step-by-step explanation:
A test cross would cross the genotype AaBb with homozygous recessive genotype aabb. The cross between AaBB x aabb would produce progeny in 1:1:1:1 ratio. So, the proportion of the progeny expressing both dominant traits (AaBb) is 1/4.
Therefore, out of the total 1000 offspring, 1/4 x 1000= 250 would express the dominant phenotype for both A and B genes.