Question

An investment is worth ​$3 comma 659 in 1992. By 1997 it has grown to $ 6 comma 659. Let y be the value of the investment in the year​ x, where xequals0 represents 1992. Write a linear equation that models the value of the investment in the year x.

Answer 1

y = 600x + 3659

Explanation:

General form of the linear equation:

y = mx + b

Given :

x = 0 represents 1992

x = 0 , y = 3659

So, x value for 1997 becomes:

x = 1997-1992 = 5

at x = 5, y = 6659

Plugging in x = 0, y = 3659 in y = mx+b

3659 = m(0) + b

b = 3659

Plugging in x = 5, y = 6659 and b = 3659

6659 = m(5) + 3659

Solving for m:

m(5) = 6659-3659

5m = 3000

m = 3000/5 = 600

Now plug in the values of unknowns m and b in general equation:

y = 600x + 3659