Question

Identify the center and radius of the circle: \left(x-7\right)^2+\left(y+3\right)^2=64

Answer 1

Center is (7,-3) and radius is 8

Explanation:

Equation of circle with (h,k) as center and radius r is given by,

(x-h)²+(y-k)² = r²

Here we need to find the radius and center of the circle given by the equation (x-7)²+(y+3)²=64

Changing equation to (x-h)²+(y-k)² = r² form

(x-7)²+(y+3)²=64

(x-7)²+(y-(-3))² = 8²

So, h = 7 , k = -3 and r = 8

Center is (7,-3) and radius is 8