Answer:
Total dinners served at the banquet = 42
Explanation:
chicken:beef:fish = 7:5:2
Chicken =
=
Beef =
=
Fish =
=
Fish > 5...........(i)
Beef + Fish < 30
+ Fish < 30
Fish < 8.57........(ii)
Beef +
< 30
Beef < 21.43.........(iii)
+
< 30
Chicken < 30.........(iv)
Chicken < 25........(v)
< 25
Fish < 7.143........(vi)
< 25
Beef < 17.857........(vii)
From (i), (ii) and (vi)
Fish > 5; Fish < 8.57; Fish <7.143;
Therefore: 5 < Fish < 7.143
So fish is either 6 or 7
From (iii) and (vii)
Beef < 21.43; Beef < 17.857;
Therefore Beef < 17.857
If Fish = 6, Beef = 15;
If Fish = 7, Beef = 17.5
From (iv) and (v)
Chicken < 30; Chicken <25;
Therefore Chicken < 25
If Fish = 6, Chicken = 21;
If Fish = 7, Beef = 24.5
Since meals must be whole numbers, Fish = 6, Beef = 15, Chicken = 21
Total = chicken + beef + fish = 21 + 15 + 6 = 42