Question

Suppose a triangle has two sides of length 2 and 3 and that angle between these two sides is 60 degrees. What is the length of the third side

Answer 1

The measure of the third side is
`√(7)\ units`

Explanation:

we know that

Applying the law of cosines

`c^2=a^2+b^2-2(a)(b)cos(C)`

where

C is the angle between side a and side b

we have

`a=2\ units\\b=3\ units\\C=60^o`

substitute

`c^2=2^2+3^2-2(2)(3)cos(60^o)`

`c^2=13-(12)((1)/(2))`

`c^2=13-6`

`c^2=7`

`c=√(7)\ units`