Question

Find the angle measuments of a triagle in which one angle measures 10 degress less than twice the second triangle, and the third angle measures 25 degrees more than the second angle.

Answer 1

Answer:the first angle is 72.5 degrees.

The second angle is 41.25 degrees.

The third angle is 66.25 degrees

Explanation:

Let x represent the size of the first angle.

Let y represent the size of the second angle.

Let y represent the size of the second angle.

one angle measures 10 degress less than twice the second triangle. This means that

x = 2y - 10

the third angle measures 25 degrees more than the second angle. This means that

z = y + 25

The sum of the angles in a triangle is 180 degrees. This means that

x + y + z = 180 - - - - - - - - - - 1

Substituting x = 2y - 10 and z = y + 25 into 1, it becomes

2y - 10 + y + y + 25 = 180

4y + 15 = 180

4y = 180 - 15 = 165

y = 165/4 = 41.25 degrees

x = 2y - 10 = 41.25 × 2 - 10 = 72.5 degrees

z = x + 25 = 41.25 + 25 = 66.25 degrees