Question

Find the slope-intercept form of the equation of the line that passes through

(–5, 3) and is parallel to 12x – 3y = 10.

Answer 1

Explanation:

12x - 3y = 10

-3y = -12x + 10

y = 4x - 10/3....the slope here is 4

parallel lines will have the same slope

y = mx + b

slope(m) = 4

(-5,3)...x = -5 and y = 3

now we sub and find b, the y int

3 = 4(-5) + b

3 = -20 + b

3 + 20 = b

23 = b

so ur equation is : y = 4x + 23 <==