2x²-3x-15=5 using the factoring method

asked Jun 21, 2021 226k views

2 votes

5.9k points

Please log in or register to add a comment.

0 votes

Answer:

$x=4,\ (-5)/(2)$

Explanation:

$2x^2-3x-15=5\\2x^2-3x-15-5=0\\2x^2-3x-20=0\\\\2x^2-8x+5x-20=0\\2x(x-4)+5(x-4)=0\\(x-4)(2x+5)=0\\if\ (x-4)=0\\x=4\\if\ (2x+5)=0\\2x=-5\\x=(-5)/(2)$

Insomnious answered Jun 26, 2021

6.3k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.2m questions

8.1m answers