Question

A 3 kg mass at rest on the floor is attached to a string which goes vertically to a pulley. A weight is attached to the other end of the string and released. If the 3 kg mass rises 50 cm in 1 s, find is the value of the other mass.

Answer 1

M = 3.68 Kg

Step-by-step explanation:

given,

mass on the floor, m = 3 Kg

mass raised to, s = 50 cm

time,t = 1 s

using equation of motion

`s = u t + (1)/(2)at^2`

s is the displacement .

initial speed = 0

`0.5=(1)/(2)* a* 1^2`

a = 1 m/s²

acceleration in terms of mass and gravity is given as

a = m g

`a = (M-m)/(M+m)* g`

M is the mass of the block hanging

`1= (M-3)/(M+3)* 9.8`

M + 3 = 9.8 M - 29.4

8.8 M = 32.4

M = 3.68 Kg

The other mass is equal to M = 3.68 Kg