Question

Elvin is asked to analyze a 0.353 gram sample of metal. He measures the amount of heat

released by cooling it from 50.0 °C to 22.0 °C as 2.28 J. What is the specific heat of this metal?
What metal could this be?​

Answer 1

c = 0.23 j/g.°C

The metal could be silver

Step-by-step explanation:

Given data:

Mass of metal = 0.353 g

Initial temperature = 50°C

Final temperature = 22.0°C

Heat release = -2.28 j

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 -T1

ΔT = 22.0°C - 50°C

ΔT = -28°C

Q = m.c. ΔT

- 2.28 j = 0.353 g × c × -28°C

c = - 2.28 j / 0.353 g × -28°C

c = - 2.28 j / 9.884g.°C

c = 0.23 j/g.°C

The metal could be silver.