Question

A professional boxer hits his opponent with a 1145-N horizontal blow that lasts for 0.122 s.

a) Calculate the impulse imparted by this blow?

Answer 1

a) The impulse imparted by this blow is 139.69 Ns

Step-by-step explanation:

The impulse is defined in many ways but here we're are going to use the definition that states average impulse is average force (blow) times the times the force is applied:

`\overrightarrow{J}=\overrightarrow{F}_(avg)(\varDelta t)`

We're only interested on magnitude because we know the force is horizontal, so the impulse is horizontal too and in the same direction the force is, So:

`J=F_(avg)(\varDelta t)=(1145N)(0.122s)`

`J=139.69Ns`