Question

Please help!! <3
Thankss in advance!:)​

Answer 1

Given:

AB is a diameter

<BOC=<COD

AO=OB=OC=OD being radius

TO PROVE :

AD // OC

CONSTUCTION:

AC is joined:

Proof:

<BOC=2<BAC

<COD=2<DAC

Being center angle is double of the inscribed angle standing on a same arc.

we get

`<DAO=(1)/(2)(<BOC+<COD)=(1)/(2)(<BOC+<BOC)`

Given

<DAO=<BOC

which satisfy the property of corresponding angle.

So, AD//OC

proved:

Explanation: