Question

Amelie spins the following spinner, which has 10 equally sized spaces numbered 1 through 10. The numbers 1 and 7 are colored blue; the numbers 2, 4, and 6 are red; and the numbers 3, 5, 8, 9, and 10 are green.

What is the probability that Amelie spins either an odd number or a red number?

Enter your answer as a reduced fraction, like this: 3/14

Answer 1

e

Explanation:

The spinner has 10 equally sized spaces.

Numbers 1 and 7 are colored blue.

Numbers 2, 4, and 6 are red.

Numbers 3, 5, 8, 9, and 10 are green.

There are three numbers or sections in the spinner are red. That means the probability of getting a red is 3/10. This fraction cannot be reduced nor simplified.

There are five sections that are odd numbers. Those are 1, 3, 5, 7, and 9. The probability of getting a odd number is 5/10. Unlike the fraction 3/10, 5/10 can be simplified. It can be reduced to 1/2.

Combined, the probability of getting both red and odd sections are 7/10. This fraction cannot be simplified.

Answer 2

The probability that Amelie spins either an odd number or a red number is 7/10

What is the probability that Amelie spins either an odd number or a red number?

From the question, we have the following parameters that can be used in our computation:

Spinner = 10 sections

Red = 2

Green = 5

Blue = 3

There are 5 odd sections

So, we have

P(Odd) = 5/10

Also, we have

P(Red) = 2/10

Lastly, we have

P(Red and Odd) = 0

Using the above as a guide, we have the following:

P(Red or Odd) = 5/10 + 2/10

Evaluate

P(Red or Odd) = 7/10

Hence, the probability that Amelie spins either an odd number or a red number is 7/10