Answer:
3.33 M
Step-by-step explanation:
It seems your question is incomplete, however, that same fragment has been found somewhere else in the web:
" A chemist prepares a solution of silver nitrate (AgNO3) by measuring out 85.g of silver nitrate into a 150.mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's silver nitrate solution. Be sure your answer has the correct number of significant digits. "
In this case, first we calculate the moles of AgNO₃, using its molecular weight:
- 85.0 g AgNO₃ ÷ 169.87 g/mol = 0.500 mol AgNO₃
Then we convert the 150 mL of the volumetric flask into L:
Finally we divide the moles by the volume:
- 0.500 mol AgNO₃ / 0.150 L = 3.33 M