Question

2. The number of nickels that Christine has is

5 times the number of dimes. Their value is
$1.05. How many coins of each type does
she have?

Answer 1

The number of nickels is 15

The number of Dimes is 3

Explanation:

Let the number of dimes Christine has be d

The number of nickels with christine be n

Then the number of Nickels Christine has will be

n = 5d ----------------------------------(1)

Now The total value of both dimes and nickels is = $1.05

This can be represented as

5n +10d = 105 (in cents)

From eq(1)

5(5d) + 10d = 105

25d+10d = 105

35d = 105

`d = (105)/(35)`

d = 3----------------------------------(2)

Substituting (2) in (1), we get

n = 5(3)

n = 15