Answer:
20
Explanation:
The new table seats 6 customers
The original table seats 4 customers
Total number of tables = 40
Total number of customers capable of seating = 220
Let new tables = x
Let original tables = y
x + y = 40 ...........(1)
6x + 4y = 220 ...........(2)
From equation (1)
x + y = 40
x = 40 - y............. (3)
Put eq(3) into eq(2)
6(40 - y) + 4y = 220
240 - 6y + 4y = 220
240 - 2y = 220
-2y = 220 - 240
-2y = -20
y = -20/ -2
y = 10
Put y=10 into eq(3)
x = 40- 10
x = 30
To find how many more new tables than the original table the restaurant has, we will subtract the number of original tables from new ones.
y - x
= 30 -10
= 20