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Explain why not all solutions represented by inequation are always possible solutions in reality.

User Jacques Bosch
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Why aren't all solutions to an inequality possible in reality?

(TL;DR at the bottom, but the full explanation is better)

Let's answer this using an example.

The equation 2x + 5 > 10 can represent a lemonade stand's sales. What do each of the numbers represent in a real-life situation?

  • x represents the amount of lemonade glasses sold
  • 2 (dollars) represents the price of each glass of lemonade
  • 5 represents the base profit that the stand opened with
  • 10 represents the goal for profit

A solution for this equation would be x = -3:

2x + 5 > 10

2(-3) + 5 > 10

6 + 5 > 10

11 > 10 - True

Another solution is x = 11/3:

2x + 5 > 10

2(11/3) + 5 > 10

(22/3) + 5 > 10

(37/3) > 10

(36/3)+(1/3) > 10

12 and (1/3) > 10

These are solutions to our inequality from a mathematical standpoint but are both implausible in real life.

Assuming that reasonable would mean a full glass, -3 and (11/3) are possible answers, but can't be reasonably sold. -3 glasses of lemonade can't be sold, and neither can (11/3) of a glass of lemonade.

Therefore, these values create a situation where "not all solutions represented by inequation are always possible solutions in reality."

TL;DR:

Not all solutions are possible because the value that makes the inequation true is not reasonable or feasible under realistic circumstances, such as a fraction value for people or a negative value for possession.

User Nimit Dudani
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